Question

A dielectric slab fills the lower half of a parallel plate capacitor as shown in figure :

(Take plate are as $A$)

This question has multiple correct options

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Correct options are A) , C) and D)

$C_{1}=2dε_{0}A $ and $C_{2}=2dKε_{0}A $

$C_{eq}=C_{1}+C_{2}=2dε_{0}A +2dKε_{0}A =2dϵ_{0}A ×(1+K)$. Hence option A is correct

$C_{1}$ is due to upper half of two plates, while $C_{2}$ is due to lower half. As potential difference across two capacitors is the same, charges would be different as capacitors are different. Hence option C is correct,

Net charge on the lower half plate

$Q_{2}=C_{2}V=2dKε_{0}A V$.

Therefore option D is correct

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