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We know that for a divergent lens both u and f are -ive , from lens equation

$v=u+fuf $ , as both u and f are -ive therefore v will be -ive ,

given $f=−30cm,v=−15cm$ ,

so $u=f−vfv =−30−(−15)−30×−15 =−30cm$ ,

now linear magnification $m=I/O=v/u$ ,

given height of object $O=5cm,I=?$ ,

therefore $I/5=15/30$ ,

or $I=5×15/30=2.5cm$

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