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Question

A domain in ferromagnetic iron is in the form of a cube of side length 2μ m then the number of iron atoms in the domain are (Molecular mass of iron = 55gmol1 and density = 7.92gcm3), maximum value of magnetisation of the given domain is (Dipole moment of an iton atom 9.27×1024Am2)
  1. 8.0×105Am1
  2. 6.0×104Am1
  3. 8.0×103Am1
  4. 6.0×103Am1

A
8.0×105Am1
B
6.0×104Am1
C
8.0×103Am1
D
6.0×103Am1
Solution
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Net dipole moment, MN=N×m=6.92×1011×9.27×1024=6.4×1012Am2
Net magnetisation =6.4×10128×1018=8×105Am1

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