A dye absorbs a photon of wavelength lambda and re-emits the same energy into two photons of wavelengths of λ1 and λ2 respectively. The wavelength lambda is related with λ1 and λ2 as:
λ=λ1+λ2λ1λ2
λ=λ1λ2λ1+λ2
λ=λ12λ22λ1+λ2
λ=λ1λ2(λ1+λ2)2
A
λ=λ1λ2λ1+λ2
B
λ=λ1λ2(λ1+λ2)2
C
λ=λ1+λ2λ1λ2
D
λ=λ12λ22λ1+λ2
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Solution
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Let E be the energy of photon with wavelength λ
E1 be the energy of photon with wavelength λ1
E2 be the energy of photon with wavelength λ2
E=E1+E2
hcλ=hcλ1+hcλ2
1λ=1λ1+1λ2
1λ=λ1+λ2λ1λ2
λ=λ1λ2λ1+λ2
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