An electric toaster of resistance 20 Omega takes a current of 5 A- Calculate the heat developed in 30 s-

Question

An electric toaster of resistance 20  Omega takes a current of 5  A- Calculate the heat developed in 30  s-

Toppr Admin · Accepted Answer

Given -xA0- current i-5-xA0-A-xA0- -xA0- resistance R-20-xA0-x3A9- - time t-30-xA0-sHeat generated-xA0- is given by H-i2RtH-52-xA0-xD7-20-xD7-30-15-000-xA0-J

An electric toaster of resistance $20 Ω$ takes a current of $5 A$ . Calculate the heat developed in $30 s$ .

Given : current $i = 5 A$ , resistance $R = 20 Ω$ , time $t = 30 s$

Heat generated is given by $H = i^{2} R t$

$H = 5^{2} \times 20 \times 30 = 15, 000 J$

An electric toaster of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Given : current i=5 A , resistance R=20 Ω , time t=30 sHeat generated is given by H=i2RtH=52 ×20×30=15,000 J

An electric toaster of resistance $20 Ω$ takes a current of $5 A$ . Calculate the heat developed in $30 s$ .

Given : current $i = 5 A$ , resistance $R = 20 Ω$ , time $t = 30 s$

Heat generated is given by $H = i^{2} R t$

$H = 5^{2} \times 20 \times 30 = 15, 000 J$