A farmer sells his product a loss of 8-If his S-P was Rs-27-600-What was his actual loss-What was his Cost price-

Question

Toppr Admin · Accepted Answer

Let the C-P of the product be Rs-100Loss-8-8- of C-P-8100-xD7-100-Rs-8S-P-C-P-x2212-Loss-Rs-100-x2212-Rs-8-Rs-92Thus if S-P is Rs-92 then C-P is Rs-100If S-P is Rs-27600 then C-P-10092-xD7-27600-Rs-30-000Hence Actual C-P-Rs-30-000Actual loss-C-P-x2212-S-P-30-000-x2212-27-600-Rs-2400

A farmer sells his product at a loss of 8%.If his S.P was Rs.27,600.What was his actual loss?What was his Cost price?

Let the C.P of the product be Rs.100Loss=8%=8% of C.P=8100×100=Rs.8S.P=C.P−Loss=Rs.100−Rs.8=Rs.92Thus if S.P is Rs.92 then C.P is Rs.100If S.P is Rs.27600 then C.P=10092×27600=Rs.30,000Hence Actual C.P=Rs.30,000Actual loss=C.P−S.P=30,000−27,600=Rs.2400

A farmer sells his product at a loss of $8 %$ .If his S.P was Rs. $27, 600$ .What was his actual loss?What was his Cost price?