A father purchases dress his three daughters- The dresses are of same color but of different size- The dress is kept in dark room- What is the probability that all the three will not choose their own dress -1-32-31-61-9

Question

Toppr Admin · Accepted Answer

The correct option is B 1-3Total no of ways of getting the dresses is 3-Out of which only 2 are such that in which there will no one with correct dress-Using dearrangement formula 3-1-2-x2212-1-3-2Hence required probability-2-3-1-3

A father purchases dress for his three daughters. The dresses are of same color but of different size. The dress is kept in dark room. What is the probability that all the three will not choose their own dress ?
1/3
2/3
1/6
1/9

The correct option is B 1/3
Total no of ways of getting the dresses is 3!
Out of which only 2 are such that in which there will no one with correct dress.
Using dearrangement formula $3! (1 / 2! - 1 / 3!) = 2$
Hence required probability $= 2! / 3! = 1 / 3$

A father purchases dress for his three daughters. The dresses are of same color but of different size. The dress is kept in dark room. What is the probability that all the three will not choose their own dress ?1/32/31/61/9

The correct option is B 1/3Total no of ways of getting the dresses is 3!Out of which only 2 are such that in which there will no one with correct dress.Using dearrangement formula 3!(1/2!−1/3!)=2Hence required probability=2!/3!=1/3

A father purchases dress for his three daughters. The dresses are of same color but of different size. The dress is kept in dark room. What is the probability that all the three will not choose their own dress ?
1/3
2/3
1/6
1/9

The correct option is B 1/3
Total no of ways of getting the dresses is 3!
Out of which only 2 are such that in which there will no one with correct dress.
Using dearrangement formula $3! (1 / 2! - 1 / 3!) = 2$
Hence required probability $= 2! / 3! = 1 / 3$