A first order reaction has a specific reaction rate of $10^{- 2} s e c^{- 1}$ . How much time will it take for $20 g$ of the reactant to reduce to $5 g$ ?

Question

A first order reaction has a specific reaction rate of 10-2- sec-1- How much time will it take 20 g of the reactant to reduce to 5 g-693-0 sec238-6  sec138-6 sec346-5 sec

Toppr Admin · Accepted Answer

The correct option is C 138-6-xA0-sect-2-303klog-aa-x2212-x-t-2-30310-x2212-2-slog-20g5g-t-138-6 secHence- the time required will be 138-6 sec-

A first order reaction has a specific reaction rate of $10^{- 2} s e c^{- 1}$ . How much time will it take for $20 g$ of the reactant to reduce to $5 g$ ?
$693.0 s e c$
$238.6 s e c$
$138.6 s e c$
$346.5 s e c$

The correct option is C $138.6 s e c$
$t = \frac{2.303}{k} l o g (\frac{a}{a - x})$

$t = \frac{2.303}{10^{- 2} / s} l o g (\frac{20 g}{5 g})$

$t = 138.6$ sec
Hence, the time required will be 138.6 sec.

A first order reaction has a specific reaction rate of 10−2sec−1. How much time will it take for 20 g of the reactant to reduce to 5 g?693.0 sec238.6 sec138.6 sec346.5 sec

The correct option is C 138.6 sect=2.303klog(aa−x)t=2.30310−2/slog(20g5g)t=138.6 secHence, the time required will be 138.6 sec.

A first order reaction has a specific reaction rate of $10^{- 2} s e c^{- 1}$ . How much time will it take for $20 g$ of the reactant to reduce to $5 g$ ?
$693.0 s e c$
$238.6 s e c$
$138.6 s e c$
$346.5 s e c$

The correct option is C $138.6 s e c$
$t = \frac{2.303}{k} l o g (\frac{a}{a - x})$

$t = \frac{2.303}{10^{- 2} / s} l o g (\frac{20 g}{5 g})$

$t = 138.6$ sec
Hence, the time required will be 138.6 sec.