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Updated on : 2022-09-05

Solution

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Correct option is D)

mass, $m=3g=0.003kg$

$x=3t−4t_{2}+t_{3}$

Now,

$v=dtdx =3−8t+3t_{2}⇒dx=(3−8t+3t_{2})dt$

$⇒a=dtdv =0−8+6t$

Now,

$dw=Fdx$

$⇒dw=(ma)dx$

$⇒dw=(0.003)(−8+6t)(3−8t+3t_{2})dt$

$⇒dw=(0.003)(18t_{3}−72t_{2}+82t−24)dt$

$⇒w=(0.003)∫_{0}(18t_{3}−72t_{2}+82t−24)dt$

$⇒w=0.003×176=0.528J$

$⇒w=530mJ$

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