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Correct option is D)

mass, $m=3Βg=0.003Βkg$

$x=3tβ4t_{2}+t_{3}$

Now,Β

$v=dtdxβ=3β8t+3t_{2}βdx=(3β8t+3t_{2})dt$

$βa=dtdvβ=0β8+6t$

Now,

$dw=Fdx$

$βdw=(ma)dx$

$βdw=(0.003)(β8+6t)(3β8t+3t_{2})dt$

$βdw=(0.003)(18t_{3}β72t_{2}+82tβ24)dt$

$βw=(0.003)β«_{0}(18t_{3}β72t_{2}+82tβ24)dt$

$βw=0.003Γ176=0.528ΒJ$

$βw=530ΒmJ$

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