A force →F=(3t^i+5^j)N acts on a body due to which its displacement varies as →S=(2t2^i−5^j)m. Work done by this force in 2 second is
32 J
24 J
46 J
20 J
A
24 J
B
46 J
C
32 J
D
20 J
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Solution
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→v=d→Sdt=(4t)^i
P=→F⋅→v=12t2
∴W=∫20Pdt=∫20(12)t2dt=32J.
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