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Question

A force F=(3t^i+5^j)N acts on a body due to which its displacement varies as S=(2t2^i5^j)m. Work done by this force in 2 second is
  1. 32 J
  2. 24 J
  3. 46 J
  4. 20 J

A
24 J
B
46 J
C
32 J
D
20 J
Solution
Verified by Toppr

v=dSdt=(4t)^i

P=Fv=12t2

W=20Pdt=20(12)t2dt=32J.

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