A force displaystyle F is given by F - - bt-2 - where t is time- The dimensions of a and b are - -M-L-T-2- and -M-L-T-0- -M-L-T-4- and -M-L-T-3- -M-L-T-3- and -M-L-T-4- -M-L-T-1- and -M-L-T-2-

Question

A force displaystyle F  is given by  F - - bt-2 - where  t  is time- The dimensions of a and b are - -M-L-T-2-  and  -M-L-T-0-  -M-L-T-4-  and  -M-L-T-3-  -M-L-T-3-  and  -M-L-T-4-  -M-L-T-1-  and  -M-L-T-2-

Toppr Admin · Accepted Answer

Dimensions of force are MLT-x2212-2- Thus- both at and bt2 must have units of force-Thus- -a-T-MLT-x2212-2 or -a-MLT-x2212-3Also- -b-T2-MLT-x2212-2 or -b-MLT-x2212-4

A force $F$ is given by $F = a t + b t^{2}$ , where $t$ is time. The dimensions of $a$ and $b$ are :
$[M L T^{- 2}]$ and $[M L T^{0}]$
$[M L T^{- 4}]$ and $[M L T^{- 3}]$
$[M L T^{- 3}]$ and $[M L T^{- 4}]$
$[M L T^{- 1}]$ and $[M L T^{- 2}]$

Dimensions of force are $M L T^{- 2}$ . Thus, both $a t$ and $b t^{2}$ must have units of force.
Thus, $| a | T = M L T^{- 2}$ or $| a | = M L T^{- 3}$
Also, $| b | T^{2} = M L T^{- 2}$ or $| b | = M L T^{- 4}$

A force F is given by F=at+bt2, where t is time. The dimensions of a and b are :[MLT−2] and [MLT0][MLT−4] and [MLT−3][MLT−3] and [MLT−4][MLT−1] and [MLT−2]

Dimensions of force are MLT−2. Thus, both at and bt2 must have units of force.Thus, |a|T=MLT−2 or |a|=MLT−3Also, |b|T2=MLT−2 or |b|=MLT−4

A force $F$ is given by $F = a t + b t^{2}$ , where $t$ is time. The dimensions of $a$ and $b$ are :
$[M L T^{- 2}]$ and $[M L T^{0}]$
$[M L T^{- 4}]$ and $[M L T^{- 3}]$
$[M L T^{- 3}]$ and $[M L T^{- 4}]$
$[M L T^{- 1}]$ and $[M L T^{- 2}]$

Dimensions of force are $M L T^{- 2}$ . Thus, both $a t$ and $b t^{2}$ must have units of force.
Thus, $| a | T = M L T^{- 2}$ or $| a | = M L T^{- 3}$
Also, $| b | T^{2} = M L T^{- 2}$ or $| b | = M L T^{- 4}$