Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Biology
Question

A foreign DNA and plasmid cut by the same restriction endonuclease can be joined to form a recombinant plasmid using
  1. Polymerase III
  2. Eco RI
  3. Ligase
  4. Taq polymerase

A
Ligase
B
Eco RI
C
Taq polymerase
D
Polymerase III
Open in App
Solution
Verified by Toppr

Polymerase III and Taq polymerase are enzymes of DNA polymerization and add deoxyribonucleotides to the primer in 5' to 3' direction. EcoRI is restriction enzyme from E. coli that digest DNA at G^AATTC sites. DNA ligase enzyme joins two DNA fragments together via phosphodiester bond between 3’ hydroxyl at the end of one fragment and a 5’ phosphate at the end of another fragment. Foreign DNA and a plasmid having complementary ends can be ligated using DNA ligase.
Therefore, the correct answer is option B.

Was this answer helpful?
0
Similar Questions
Q1
A foreign DNA and plasmid cut by the same restriction endonuclease can be joined to form recombinant plasmid using

View Solution
Q2
From the below list, which of the following is the most logical sequence of steps for splicing foreign DNA into a plasmid and inserting the plasmid into a bacterium?
(i) Transformbacteria with recombinant DNA molecule.
(ii) Cut the plasmid DNA using restriction enzymes.
(iii) Extract plasmid DNA from bacterial cells.
(iv) Hydrogen-bond the plasmid DNA to nonplasmid DNA fragments.
(v) Use ligase to seal plasmid DNA to nonplasmid DNA.
View Solution
Q3
Arrange the following steps of formation of recombinant DNA in the correct sequence.
I. Complementary sticky ends are produced on the foreign DNA and the plasmid.
II. Foreign DNA and plasmids are mixed together
III. DNA ligase is used to seal the nicks in the sugar–phosphate backbone.
IV. Cut the foreign DNA (containing the DNA fragment of interest) and the plasmid with the same restriction enzyme.
View Solution
Q4
A piece of foreign DNA was inserted into a plasmid with an antibiotic resistance gene and lactose Z gene. The plasmid DNA was cut with a restriction enzyme, which splits the lactose Z gene and opens the circle. The foreign DNA was next inserted into the open restriction site of the plasmid. When the recombinant plasmid was introduced into bacterial cells and grown in the presence of antibiotic, some of the colonies turned blue in the presence of gene. The blue colonies contained
View Solution
Q5
Following steps are involved in cloning a eukaryotic gene in a bacterial plasmid vector.
I. Introduction of cloning vector into cells.
II. Insertion of eukaryotic DNA into the vector.
III. Identification of cell clones that carry the inserted eukaryotic gene.
IV. Isolation of the vector and the eukaryotic gene-source DNA.
V. Cloning of cells (and foreign DNA).
Which of the following statemet is the correct reason for the insertion of eukaryotic DNA into the plasmid vector, the sticky ends formed by digestion of both DNA types with the same restriction enzyme may join in a recombinant molecule?
View Solution