A galvanometer coil has a resistance of 12 Omega and the metre shows full scale deflection a current of 3 mA- How will you convert the metre into a voltmeter of range 0 to 18 V-

Question

A galvanometer coil has a resistance of 12 Omega  and the metre shows full scale deflection a current of 3 mA- How will you convert the metre into a voltmeter of range 0 to 18 V-

Toppr Admin · Accepted Answer

Converting galvanometer into voltmeter is done by adding resistance in series-The resistance is given by R-VIg-x2212-G-xA0-G is resiatance of galvanometer-x21D2-R-5988-x3A9-

A galvanometer coil has a resistance of 12 $Ω$ and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V?

Converting galvanometer into voltmeter is done by adding resistance in series.
The resistance is given by $R = \frac{V}{I_{g}} - G; G$ is resiatance of galvanometer.
$\Rightarrow R = 5988 Ω$

A galvanometer coil has a resistance of 12 Ω and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V?

Converting galvanometer into voltmeter is done by adding resistance in series.The resistance is given by R=VIg−G; G is resiatance of galvanometer.⇒R=5988Ω

A galvanometer coil has a resistance of 12 $Ω$ and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V?

Converting galvanometer into voltmeter is done by adding resistance in series.
The resistance is given by $R = \frac{V}{I_{g}} - G; G$ is resiatance of galvanometer.
$\Rightarrow R = 5988 Ω$