A galvanometer coil has a resistance of $150 Ω$ gives full-scale deflection for a current of $4 m A$ . To convert it to an ammeter of range $0$ to $6 A$

Question

A galvanometer coil has a resistance of 15 Omega and the metre shows full scale deflection a current of 4 mA- How will you convert the metre into an ammeter of range 0 to 6 A-

Toppr Admin · Accepted Answer

G-15-x3A9-Current for which- the galvanometer shows full scale deflection- i-4mA-Range of ammeter is 4 mA- which needs to be converted to 6A-x2234-I-6AA short resistance R is to be connected in parallel to the galvanometer-R-iG-I-x2212-i-10m-x3A9-

A galvanometer coil has a resistance of $15 Ω$ and the metre shows full scale deflection for a current of $4 m A$ . How will you convert the metre into an ammeter of range $0$ to $6 A$ ?

$G = 15 Ω$
Current for which, the galvanometer shows full scale deflection, $i = 4 m A$ .
Range of ammeter is 4 mA, which needs to be converted to $6 A$ .
$∴ I = 6 A$
A short resistance $R$ is to be connected in parallel to the galvanometer.
$R = i G / (I - i) = 10 m Ω$

A galvanometer coil has a resistance of 15 Ω and the metre shows full scale deflection for a current of 4 mA. How will you convert the metre into an ammeter of range 0 to 6 A?

G=15ΩCurrent for which, the galvanometer shows full scale deflection, i=4mA.Range of ammeter is 4 mA, which needs to be converted to 6A.∴I=6AA short resistance R is to be connected in parallel to the galvanometer.R=iG/(I−i)=10mΩ

A galvanometer coil has a resistance of $15 Ω$ and the metre shows full scale deflection for a current of $4 m A$ . How will you convert the metre into an ammeter of range $0$ to $6 A$ ?

$G = 15 Ω$
Current for which, the galvanometer shows full scale deflection, $i = 4 m A$ .
Range of ammeter is 4 mA, which needs to be converted to $6 A$ .
$∴ I = 6 A$
A short resistance $R$ is to be connected in parallel to the galvanometer.
$R = i G / (I - i) = 10 m Ω$