0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A gas) +B (gas) In the reaction AB The value of K is equal to 1/3 rd of total equilibrium pressure. What is the percentage dissociation of AB? A) 25 % B) 30% C) 54 % D) 50%

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
The dissociation equilibrium of a gas AB2 can be represented as, 2AB2(g)2AB(g)+B2(g).
The degree of dissociation is x and is small as compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kp and total pressure P is:
View Solution
Q2
For the reaction: AB(g)A(g)+B(g),
AB is 25% dissociated at a total pressure of P. Then,
View Solution
Q3

A gas for which γ=43, is heated at constant pressure. The percentage of total heat supplied for doing external work is


View Solution
Q4

The dissociation equilibrium of a gas AB2 can be represented as:

2AB2(g)ā‡Œ2AB(g)+B2(g)
The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation x with equilibrium constant Kp and total pressure p is?


View Solution
Q5
At 444^Ā° C, the equilibrium constant K for the reaction 2AB gives A2 +B2,The degree of dissociation of AB will be -(A) 10%(C) 30%(B) 20(D) 50%
View Solution