A gas has a volume of V cm-3 10-oC- If the pressure is doubled- what temperature will the volume still be V cm-3-

Question

Toppr Admin · Accepted Answer

Correct option is D- -293-o-C-dfrac-P-1V-1-T-1-dfrac-P-2V-2-T-2-dfrac-PV-283-dfrac-2P-times V-T-T-2-times 283-T-566-K-T-566-273-T-293-o-CAnswer option C-

A gas has a volume of V $$cm^3$$ at $$10^o$$C. If the pressure is doubled, at what temperature will the volume still be V $$cm^3$$?

Correct option is D. $$293^o$$C
$$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$$

$$\dfrac{PV}{283}=\dfrac{2P\times V}{T}$$

$$T=2\times 283$$

$$T=566$$K

$$T=566-273$$

$$T=293^o$$C

Answer option C.

A gas has a volume of V $$cm^3$$ at $$10^o$$C. If the pressure is doubled, at what temperature will the volume still be V $$cm^3$$?

Correct option is D. $$293^o$$C$$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$$$$\dfrac{PV}{283}=\dfrac{2P\times V}{T}$$$$T=2\times 283$$$$T=566$$K$$T=566-273$$$$T=293^o$$CAnswer option C.

Correct option is D. $$293^o$$C
$$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$$

$$\dfrac{PV}{283}=\dfrac{2P\times V}{T}$$

$$T=2\times 283$$

$$T=566$$K

$$T=566-273$$

$$T=293^o$$C

Answer option C.