A gas 'X', when dissolved in water heat, is evolved. Then solubility of 'X' will increase at:
low pressure, high temperature
high pressure, high temperature
high pressure, low temperature
low pressure, low temperature
A
low pressure, high temperature
B
low pressure, low temperature
C
high pressure, high temperature
D
high pressure, low temperature
Open in App
Solution
Verified by Toppr
X(g)+H2O(l)⇌solution;△H<0
Since, △H<0, the reaction is exothermic. So by applying Le Chatelier's principle, we can see that on increasing the temperature, the reaction shift towards the reactant side.
So, the favourable condition for temperature is low temperature.
Now, when gas is dissolved in water, its volume decreases. So, an increase of pressure will favour dissolution of gas in a liquid.
Was this answer helpful?
4
Similar Questions
Q1
A gas behaves more closely as an ideal gas at
(a) low pressure and low temperature
(b) low pressure and high temperature
(c) high pressure and low temperature
(d) high pressure and high temperature.
View Solution
Q2
In the gaseous equilibrium H2X2(g)+heat⇌2HX(g), the formation of HX will be favoured by
View Solution
Q3
Which of the following represent the suitable conditions for the liquefaction of gases?
(a) low temperature, low pressure (b) high temperature, low pressure
(c) low temperature, high pressure (d) high temperature, high pressure
View Solution
Q4
In the reaction A(g) + 2B(g) ⇌ C(g) + Q kJ of heat, more product will be obtained
or the forward reaction is favoured by
View Solution
Q5
Manufacture of ammonia from the elements is represented as,
N2 + 3H2 ⇌ 2NH3 + 22.4 k cals. The maximum yield of ammonia will be obtained when the process is made to take place: