A geostationary satellite is revolving at a height 6R above the earth's surface, where R is the radius of earth. The period of revolution of satellite orbiting at a height 2.5 R above the earth's surface will be:-

24 hours

12 hours

6 hours

6√2 hours

A

24 hours

B

12 hours

C

6 hours

D

6√2 hours

Open in App

Solution

Verified by Toppr

Was this answer helpful?

2

Similar Questions

Q1

A geostationary satellite is revolving at a height 6R above the earth's surface, where R is the radius of earth. The period of revolution of satellite orbiting at a height 2.5R above the earth's surface will be.

View Solution

Q2

A geostationary satellite is orbiting the earth at a height 6R above the surface of the earth, where R is the radius of earth. The time period of another satellite revolving around earth at a height 2.5R from earth's surface is :

View Solution

Q3

A geostationary satellite is orbiting the earth at a height 6R above the earth's surface, where R is radius of earth. The time period of another satellite at a height 2.5R from earth's surface would be:

View Solution

Q4

A geostationary satellite is revolving at a height 5R from the earth's surface, where R is radius of earth. The time period of a satellite which is at a height of R from earth's surface will be?

View Solution

Q5

A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth; R being the radius of the earth. What will be the time period of another satellite at a height 2.5 R from the surface of the earth?