A gets as many marks less than B as B gets less than C. If the total marks secured together by them is 270 and C got 90 marks more than A, find the marks secured by then individually?
30,60,180
45,90,135
40,80,150
35,70,165
A
35,70,165
B
30,60,180
C
45,90,135
D
40,80,150
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Solution
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Given B−A=C−Bor2B=A+C
A+B+C=270andC=90+A
So, we can say 3B=270B=90
180=A+C180=A+A+90A=45
So,C scored 135.
A gets 45, B gets 90 and C gets 135,
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