A girl is carrying a school bag of 3 kg mass on her back and moves 200 m on a levelled road. If the value of g be 10 m/s², the work done by the girl against the gravitational force will be :

(a) 6000 J
(b) 0.6 J
(c) 0 J
(d) 6 J

Question

Toppr Admin · Accepted Answer

The amount of work done is expressed in the equation- W-F-dcos-x3B8- In this case- the total work done is zero as the displacement is perpendicular to the applied force-

A girl is carrying a school bag of $3 k g$ mass on her back and moves $200 m$ on a leveled road. The work done against the gravitational force will be ( $g = 10 m / s^{2}$ ) :
$6 J$
$Z e r o$
None of these
$6 \times 10^{3} J$
$0.6 J$

The amount of work done is expressed in the equation: $W = F . d c o s θ$ . In this case, the total work done is zero as the displacement is perpendicular to the applied force.

A girl is carrying a school bag of 3 kg mass on her back and moves 200 m on a leveled road. The work done against the gravitational force will be (g=10 m/s2) :6 JZeroNone of these6×103 J0.6 J

The amount of work done is expressed in the equation: W=F.dcosθ. In this case, the total work done is zero as the displacement is perpendicular to the applied force.

A girl is carrying a school bag of $3 k g$ mass on her back and moves $200 m$ on a leveled road. The work done against the gravitational force will be ( $g = 10 m / s^{2}$ ) :
$6 J$
$Z e r o$
None of these
$6 \times 10^{3} J$
$0.6 J$

The amount of work done is expressed in the equation: $W = F . d c o s θ$ . In this case, the total work done is zero as the displacement is perpendicular to the applied force.