A glass prism of refractive index 1-5 is placed in water of refractive index 1-33- The minimum value of the angle of the prism so that it will not be possible to have any emergent ray is -150-circ-165-circ-180-circ-125-circ-

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Toppr Admin · Accepted Answer

-x3BC-prism- 1-5-xA0-x3BC-water -1-33-x3BC-r-1-51-33-x3B8-cric-sin-x2212-1-1-x3BC-r-sin-x2212-1-1-331-5-62-5-x2218-Maximum possible angle A is given by-xA0-A-2-x3B8-cric-125-x2218-

A glass prism of refractive index $1.5$ is placed in water of refractive index $1.33$ . The minimum value of the angle of the prism so that it will not be possible to have any emergent ray is :
$150^{\circ}$
$165^{\circ}$
$180^{\circ}$
$125^{\circ}$

$μ_{p r i s m} =$ $1.5$
$μ_{w a t e r}$ $= 1.33$

$μ_{r} = \frac{1.5}{1.33}$

$θ_{c r i c} = s i n^{- 1} (\frac{1}{μ_{r}}) = s i n^{- 1} (\frac{1.33}{1.5}) = {62.5}^{\circ}$

Maximum possible angle A is given by: $A = 2 θ_{c r i c} = 125^{\circ}$

A glass prism of refractive index 1.5 is placed in water of refractive index 1.33. The minimum value of the angle of the prism so that it will not be possible to have any emergent ray is :150∘165∘180∘125∘

μprism= 1.5 μwater =1.33μr=1.51.33θcric=sin−1(1μr)=sin−1(1.331.5)=62.5∘Maximum possible angle A is given by: A=2θcric=125∘

A glass prism of refractive index $1.5$ is placed in water of refractive index $1.33$ . The minimum value of the angle of the prism so that it will not be possible to have any emergent ray is :
$150^{\circ}$
$165^{\circ}$
$180^{\circ}$
$125^{\circ}$

$μ_{p r i s m} =$ $1.5$
$μ_{w a t e r}$ $= 1.33$

$μ_{r} = \frac{1.5}{1.33}$

$θ_{c r i c} = s i n^{- 1} (\frac{1}{μ_{r}}) = s i n^{- 1} (\frac{1.33}{1.5}) = {62.5}^{\circ}$

Maximum possible angle A is given by: $A = 2 θ_{c r i c} = 125^{\circ}$