A glass was filled with 10 ounces of water- and 0-01 ounce of the water evaporated each day during a 20-day period- What percent of the original amount of water evaporated during this period-0-002-0-02-0-2-2-20-

Question

Toppr Admin · Accepted Answer

The correct option is D 2-Given that 0-01 ounce-xA0-of water evaporates every daySo-xA0-In 20 days 20-xD7-0-01-0-2 ounces of water evaporated- of water evaporated - 0-210-xD7-100-2-So- correct answer will be option D-

A glass was filled with $10$ ounces of water, and $0.01$ ounce of the water evaporated each day during a $20$ -day period. What percent of the original amount of water evaporated during this period?
$0.002 %$
$0.02 %$
$0.2 %$
$2 %$
$20 %$

The correct option is D $2 %$
Given that 0.01 ounce of water evaporates every day
So, In 20 days $20 \times 0.01 = 0.2$ ounces of water evaporated.
% of water evaporated = $\frac{0.2}{10} \times 100 = 2 %$
So, correct answer will be option D.

A glass was filled with 10 ounces of water, and 0.01 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period?0.002%0.02%0.2%2%20%

The correct option is D 2%Given that 0.01 ounce of water evaporates every daySo, In 20 days 20×0.01=0.2 ounces of water evaporated.% of water evaporated = 0.210×100=2%So, correct answer will be option D.

A glass was filled with $10$ ounces of water, and $0.01$ ounce of the water evaporated each day during a $20$ -day period. What percent of the original amount of water evaporated during this period?
$0.002 %$
$0.02 %$
$0.2 %$
$2 %$
$20 %$

The correct option is D $2 %$
Given that 0.01 ounce of water evaporates every day
So, In 20 days $20 \times 0.01 = 0.2$ ounces of water evaporated.
% of water evaporated = $\frac{0.2}{10} \times 100 = 2 %$
So, correct answer will be option D.