A gram mole of a gas at 127oC expands isothermally until its volume is doubled. find the amount of work done and heat absorbed.
548cal
548J
238J
238cal
A
238cal
B
548J
C
238J
D
548cal
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Solution
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Work done in an isothermal process is given as W=RTln(V2V1) =8.314×400×ln2 =2310.1J=548cal
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