A group consists of 4 girls and 7 boys- In how many ways can a team of 5 members be selected is the team has no girl -

Question

Toppr Admin · Accepted Answer

Correct option is A- -21-Girls in the groups -4-Boys in the groups -5-If no girls is selected then all the candidates should be boys-160-Total Number of ways -4C-0 -times -7C-5-dfrac -4-4-times 1-times -dfrac -7-2- 5-21- ways-

A group consists of $$4$$ girls and $$7$$ boys. In how many ways can a team of $$5$$ members be selected is the team has no girl ?

Correct option is A. $$21$$
Girls in the groups $$=4$$
Boys in the groups $$=5$$
If no girls is selected then all the candidates should be boys
Total Number of ways $$=^4C_0 \times ^7C_5$$
$$=\dfrac {4!}{4!\times 1}\times \dfrac {7!}{2!\ 5!}$$
$$=21$$ ways.

A group consists of $$4$$ girls and $$7$$ boys. In how many ways can a team of $$5$$ members be selected is the team has no girl ?

Correct option is A. $$21$$Girls in the groups $$=4$$Boys in the groups $$=5$$If no girls is selected then all the candidates should be boys Total Number of ways $$=^4C_0 \times ^7C_5$$$$=\dfrac {4!}{4!\times 1}\times \dfrac {7!}{2!\ 5!}$$$$=21$$ ways.

Correct option is A. $$21$$
Girls in the groups $$=4$$
Boys in the groups $$=5$$
If no girls is selected then all the candidates should be boys
Total Number of ways $$=^4C_0 \times ^7C_5$$
$$=\dfrac {4!}{4!\times 1}\times \dfrac {7!}{2!\ 5!}$$
$$=21$$ ways.