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Number of ways of selecting a team with 1 boy and 2 girls$=_{5}C_{1}._{n}C_{2}$

Number of ways of selecting a team with 2 boy and 1 girls$=_{5}C_{2}._{n}C_{1}$

$5⋅2!n(n−1) +10⋅n=1750$

$n_{2}+3n=700$

$n_{2}+3n=700$

$∴n=25$.

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