A heap of circle is in the form of a cone of diameter 12 cm- and height 8 cm- Find its volume- How much canvas cloth is required cover the heap-

Question

Toppr Admin · Accepted Answer

Diameter of the conical heap -12- cm-Radius of heap -dfrac -12-2-6- m-Height of the cone -h-8- m-Volume of teh cone -V-dfrac -1-3-pi r-2 h-dfrac -1-3-times -dfrac -22-7-times-160-6-times-160-6-times-160-8-301-71- m-3-

A heap of circle is in the form of a cone of diameter $$12\ cm$$, and height $$8\ cm$$. Find its volume? How much canvas cloth is required cover the heap?

Diameter of the conical heap $$=12\ cm$$
Radius of heap $$=\dfrac {12}{2}=6\ m$$
Height of the cone $$=h=8\ m$$
Volume of teh cone $$=V=\dfrac {1}{3}\pi r^2 h$$
$$=\dfrac {1}{3}\times \dfrac {22}{7}\times 6\times 6\times 8=301.71\ m^3$$

A heap of circle is in the form of a cone of diameter $$12\ cm$$, and height $$8\ cm$$. Find its volume? How much canvas cloth is required cover the heap?

Diameter of the conical heap $$=12\ cm$$Radius of heap $$=\dfrac {12}{2}=6\ m$$Height of the cone $$=h=8\ m$$Volume of teh cone $$=V=\dfrac {1}{3}\pi r^2 h$$$$=\dfrac {1}{3}\times \dfrac {22}{7}\times 6\times 6\times 8=301.71\ m^3$$

Diameter of the conical heap $$=12\ cm$$
Radius of heap $$=\dfrac {12}{2}=6\ m$$
Height of the cone $$=h=8\ m$$
Volume of teh cone $$=V=\dfrac {1}{3}\pi r^2 h$$
$$=\dfrac {1}{3}\times \dfrac {22}{7}\times 6\times 6\times 8=301.71\ m^3$$