A heap of wheat is in the form of a cone of diameter 16-8m and height 3-5m- How much of cloth is required to just cover the heap-

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Toppr Admin · Accepted Answer

D-16-8-xA0-m-x27F9-r-8-4-xA0-mh-3-5-xA0-mSlant height -l-x221A-r2-h2-x221A-8-42-3-5-2-9-1-xA0-mCloth required to cover the heap-x3C0-rl-227-xD7-3-5-xD7-9-1-100-1-xA0-m2

A heap of wheat is in the form of a cone of diameter $16.8$ m and height $3.5$ m. How much of cloth is required to just cover the heap?

$d = 16.8 m ⟹ r = 8.4 m$
$h = 3.5 m$
Slant height $(l) = \sqrt{r^{2} + h^{2}} = \sqrt{({8.4}^{2}) + (3.5)^{2}} = 9.1 m$
Cloth required to cover the heap $= π r l$
$= \frac{22}{7} \times 3.5 \times 9.1 = 100.1 m^{2}$

A heap of wheat is in the form of a cone of diameter 16.8m and height 3.5m. How much of cloth is required to just cover the heap?

d=16.8 m⟹r=8.4 mh=3.5 mSlant height (l)=√r2+h2=√(8.42)+(3.5)2=9.1 mCloth required to cover the heap=πrl=227×3.5×9.1=100.1 m2

A heap of wheat is in the form of a cone of diameter $16.8$ m and height $3.5$ m. How much of cloth is required to just cover the heap?

$d = 16.8 m ⟹ r = 8.4 m$
$h = 3.5 m$
Slant height $(l) = \sqrt{r^{2} + h^{2}} = \sqrt{({8.4}^{2}) + (3.5)^{2}} = 9.1 m$
Cloth required to cover the heap $= π r l$
$= \frac{22}{7} \times 3.5 \times 9.1 = 100.1 m^{2}$