Consider a small element dx of the rod at a distance x from the left end of the rod.
Mass of this small element is dM=MLdx,
Distance of this small element from mass m is x+h
Force on m due to this small element is dF=GmdM(x+h)2
To get the total force F on the mass m, we integrate dF from x=0 to x=L
F=∫x=Lx=0GmMLdx(x+h)2=−GmML(1(L+h)−1h)=GMmh(L+h)
So, the force on m due to homogeneous bas is =GMmh(L+h).
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