A Joker-s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm- Find the area of the sheet required to 10 such caps-

Question

Toppr Admin · Accepted Answer

Correct option is A- -5500- -cm-2-We have-r-7-cm and -h-24-cm-therefore l-sqrt-r-2-h-2-sqrt-49-576-25-cm-Therefore- Required area -10-times- area of the sheet-10-times -pi rl-10-times -dfrac-22-7-times 7-times 25-5500cm-2-

A Joker's cap is in the form of a right circular cone of base radius $$7$$ cm and height $$24$$ cm. Find the area of the sheet required to make $$10$$ such caps.

Correct option is A. $$5500$$ $$cm^2$$.
We have,
$$r=7$$cm and $$h=24$$cm.

$$\therefore l=\sqrt{r^2+h^2}=\sqrt{49+576}=25$$cm.

Therefore, Required area $$=10\times$$ area of the sheet
$$=10\times \pi rl=10\times \dfrac{22}{7}\times 7\times 25=5500cm^2$$.

A Joker's cap is in the form of a right circular cone of base radius $$7$$ cm and height $$24$$ cm. Find the area of the sheet required to make $$10$$ such caps.

Correct option is A. $$5500$$ $$cm^2$$.We have,$$r=7$$cm and $$h=24$$cm.$$\therefore l=\sqrt{r^2+h^2}=\sqrt{49+576}=25$$cm.Therefore, Required area $$=10\times$$ area of the sheet$$=10\times \pi rl=10\times \dfrac{22}{7}\times 7\times 25=5500cm^2$$.

Correct option is A. $$5500$$ $$cm^2$$.
We have,
$$r=7$$cm and $$h=24$$cm.

$$\therefore l=\sqrt{r^2+h^2}=\sqrt{49+576}=25$$cm.

Therefore, Required area $$=10\times$$ area of the sheet
$$=10\times \pi rl=10\times \dfrac{22}{7}\times 7\times 25=5500cm^2$$.