A kangaroo is capable of jumping to a height of $2.62 m$ . Determine the takeoff speed of the kangaroo.
$7.17 m$
$7.7 m / s$
$7.1 m / s$
$7.17 m / s$

Question

A kangaroo is capable of jumping to a height of 2-62 m- Determine the takeoff speed of the kangaroo- 7-17 m7-7 m-s7-1 m-s7-17 m-s

Toppr Admin · Accepted Answer

Maximum height reached by Kangaroo-xA0- H-2-62Final velocity at the maximum height-xA0-xA0- v-0Acceleration due to gravity-xA0-xA0- g-x2212-9-8-xA0-m-s2-xA0-xA0-xA0- -minus sign for downward direction-Using-xA0-xA0- v2-x2212-u2-2gH-x2234-xA0-xA0- 0-x2212-u2-2-x2212-9-8-2-62-x27F9-xA0-u-x221A-2-9-8-2-62-7-17-xA0-m-s

A kangaroo is capable of jumping to a height of 2.62m. Determine the takeoff speed of the kangaroo. 7.17m7.7m/s7.1m/s7.17m/s

Maximum height reached by Kangaroo H=2.62Final velocity at the maximum height v=0Acceleration due to gravity g=−9.8 m/s2 (minus sign for downward direction)Using v2−u2=2gH∴ 0−u2=2(−9.8)(2.62)⟹ u=√2(9.8)(2.62)=7.17 m/s

A kangaroo is capable of jumping to a height of $2.62 m$ . Determine the takeoff speed of the kangaroo.
$7.17 m$
$7.7 m / s$
$7.1 m / s$
$7.17 m / s$

Maximum height reached by Kangaroo $H = 2.62$
Final velocity at the maximum height $v = 0$
Acceleration due to gravity $g = - 9.8 m / s^{2}$ (minus sign for downward direction)
Using $v^{2} - u^{2} = 2 g H$
$∴$ $0 - u^{2} = 2 (- 9.8) (2.62)$
$⟹ u = \sqrt{2 (9.8) (2.62)} = 7.17 m / s$