A kite flying a height of 75 m from the ground is attached to a straight string Which is inclined an angle of displaystyle 60-circ- to the ground The length of the string is75 mdisplaystyle 50sqrt-3-m50 mdisplaystyle 75sqrt-3-m

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Toppr Admin · Accepted Answer

Sin-x2061-60-x2218-75x-xA0-xA0-xA0-xA0-xA0-

A kite flying at a height of 75 m from the ground is attached to a straight string Which is inclined at an angle of $60^{\circ}$ to the ground The length of the string is
75 m
$50 \sqrt{3} m$
50 m
$75 \sqrt{3} m$

$sin 60 = \frac{75}{x}$

$x = \frac{75}{sin 60}$ = $\frac{75}{\frac{\sqrt{3}}{2}}$ = $\frac{150}{\sqrt{3}}$ = $50\sqrt{3}$ .

A kite flying at a height of 75 m from the ground is attached to a straight string Which is inclined at an angle of 60∘ to the ground The length of the string is75 m50√3m50 m75√3m

sin⁡60∘=75x = = = .

A kite flying at a height of 75 m from the ground is attached to a straight string Which is inclined at an angle of $60^{\circ}$ to the ground The length of the string is
75 m
$50 \sqrt{3} m$
50 m
$75 \sqrt{3} m$

$sin 60 = \frac{75}{x}$

$x = \frac{75}{sin 60}$ = $\frac{75}{\frac{\sqrt{3}}{2}}$ = $\frac{150}{\sqrt{3}}$ = $50\sqrt{3}$ .