Question

A kite is flying with the string inclined at ${45}^{\circ }$ to the horizontal If the string is straight and 50 m long the height at which the kite is flying is

• A. $25\sqrt{2}m$
• B. $50\sqrt{2}m$
• C. 25 m
• D. 50 m

Answer 1

Answer: (A)

$\sin {45}^{\circ }=\frac{h}{50}$ or $\frac{1}{\sqrt{2}}=\frac{h}{50}$
or h=$\frac{50}{\sqrt{2}}=\frac{2\times 25}{\sqrt{2}}=25\sqrt{2}$