A light beam is travelling from Region I to Region IV (Refer Figure). The refractive index in Regions I, II, III and IV are n0,n02,n06 and n08, respectively. The angle of incidence θ for which the beam just misses entering Region IV is
sin−1(34)
sin−1(18)
sin−1(14)
sin−1(13)
A
sin−1(34)
B
sin−1(13)
C
sin−1(18)
D
sin−1(14)
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Solution
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Total internal reflection occurs at the interface of region III and IV as shown in figure.
n0sinθ=no2sinθ1=no6sinθ2=no8sinr
n0sinθ=n08sin900⇒θ=sin−1(18)
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