A liquid flowing with speed through a horizontal pipe of cross sectional area A enters into another pipe of double the area of cross section- Now- the speed of the liquid isv2 vv-2v-4

Question

Toppr Admin · Accepted Answer

The correct option is C v-2initially areaA-velocity-v-Discharge-Q-A-vv2-2vdischarge will remain same-so v2-Q2A-v-A2A-v2

A liquid flowing with speed v through a horizontal pipe of cross sectional area A enters into another pipe of double the area of cross section. Now, the speed of the liquid is
v
2 v
v/2
v/4

The correct option is C v/2
initially area $A; v e l o c i t y = v; D i s c h a r g e = Q = A . v$
$v_{2} = 2 v$
discharge will remain same.
so $v_{2} = \frac{Q}{2 A} = \frac{v . A}{2 A} = \frac{v}{2}$

A liquid flowing with speed v through a horizontal pipe of cross sectional area A enters into another pipe of double the area of cross section. Now, the speed of the liquid isv2 vv/2v/4

The correct option is C v/2initially areaA;velocity=v;Discharge=Q=A.vv2=2vdischarge will remain same.so v2=Q2A=v.A2A=v2

A liquid flowing with speed v through a horizontal pipe of cross sectional area A enters into another pipe of double the area of cross section. Now, the speed of the liquid is
v
2 v
v/2
v/4

The correct option is C v/2
initially area $A; v e l o c i t y = v; D i s c h a r g e = Q = A . v$
$v_{2} = 2 v$
discharge will remain same.
so $v_{2} = \frac{Q}{2 A} = \frac{v . A}{2 A} = \frac{v}{2}$