A luminous object is placed at a distance of 30 cm from a convex lens of focal length 20 cm. On the other side of the lens, at what distance from the lens must a convex mirror of radius of curvature 10 cm be placed in order to have an upright image of the object coincident with it ?

Question

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Answer 1

Using the lens formula,
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$u = - 30 c m$ $f = 20$ cm, gives
$v = 60$ cm.
For coincidence this image should form at the centre of curvature of the mirror,
Since the radius of curvature is 10, the distance between the lens and the mirror will be $60 - 10 = 50$ cm

Answer 2

Using the lens formula,

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

u = - 30 c m

f = 20

cm, gives

v = 60

cm.
For coincidence this image should form at the centre of curvature of the mirror,
Since the radius of curvature is 10, the distance between the lens and the mirror will be

60 - 10 = 50

cm

A luminous object is placed at a distance of 30 cm from a convex lens of focal length 20 cm. On the other side of the lens, at what distance from the lens must a convex mirror of radius of curvature 10 cm be placed in order to have an upright image of the object coincident with it ?

30 cm

40 cm

50 cm

12 cm

A luminous object is placed at a distance of 30 cm from the convex lens of focal length 20 cm. On the other side of the lens, at what distance from the lens a convex mirror of radius of curvature 10 cm be placed in order to have an upright image of the object coincident with it

An object is placed at a distance of $15$ cm from a convex lens of focal length $10$ cm. On the other side of the lens, a convex mirror is placed at its focus such that the image formed by the combination coincides with the object itself. The focal length of the convex mirror is :

The size of the image of an object, which is at infinity, as formed by a convex lens of focal length $30 c m$ is $2 c m$ . If a concave lens of focal length $20 c m$ is placed between the convex lens and the image at a distance of $26 c m$ from the convex lens, calculate the new size of the images.

Revise with Concepts

Combination of Lenses in Contact

Problems on Lenses

A luminous object is placed at a distance of 30 cm from a convex lens of focal length 20 cm. On the other side of the lens, at what distance from the lens must a convex mirror of radius of curvature 10 cm be placed in order to have an upright image of the object coincident with it ?

30 cm

40 cm

50 cm

12 cm

Using the lens formula, v1​−u1​=f1​ u=−30cm f=20cm, gives v=60 cm. For coincidence this image should form at the centre of curvature of the mirror, Since the radius of curvature is 10, the distance between the lens and the mirror will be 60−10=50 cm

A luminous object is placed at a distance of 30 cm from the convex lens of focal length 20 cm. On the other side of the lens, at what distance from the lens a convex mirror of radius of curvature 10 cm be placed in order to have an upright image of the object coincident with it

An object is placed at a distance of 15 cm from a convex lens of focal length 10 cm. On the other side of the lens, a convex mirror is placed at its focus such that the image formed by the combination coincides with the object itself. The focal length of the convex mirror is :

The size of the image of an object, which is at infinity, as formed by a convex lens of focal length 30 cm is 2 cm. If a concave lens of focal length 20 cm is placed between the convex lens and the image at a distance of 26 cm from the convex lens, calculate the new size of the images.

Revise with Concepts

Combination of Lenses in Contact

Problems on Lenses

An object is placed at a distance of $15$ cm from a convex lens of focal length $10$ cm. On the other side of the lens, a convex mirror is placed at its focus such that the image formed by the combination coincides with the object itself. The focal length of the convex mirror is :

The size of the image of an object, which is at infinity, as formed by a convex lens of focal length $30 c m$ is $2 c m$ . If a concave lens of focal length $20 c m$ is placed between the convex lens and the image at a distance of $26 c m$ from the convex lens, calculate the new size of the images.