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>> $A magnet has coercivity of 3 \times 10^3 Am^$

Question

A magnet has coercivity of $3 \times 1 0^{3}$ $A m^{- 1}$ . It is kept in a $10$ cm long solenoid with a total of $50$ turns. How much current has to be passed through the solenoid to demagnetize it?

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Updated on : 2022-09-05

Solution

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$μ_{\circ} H = μ_{\circ} n I$
Given:
where $H = 3 \times 1 0^{- 3} A m^{- 1} =$ coercivity
$n =$ number of turns per unit length $= \frac{5 0}{0 . 1} = 500 m^{- 1}$
To find: $I =$ current
Now
$H = n I$
$3 \times 1 0^{- 3} A m^{- 1} = 500 m^{- 1} \times I$
$I = 6 \times 1 0^{- 6} A = 6 μ A$

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