A magnet of magnetic moment 20 CGS is freely suspended in a uniform magnetic field of intensity 0-3 CGS units- The moment of work done in deflecting it by an angle of 30-circ- in CGS is63-2 - sqrt -3-3 sqrt -3-3

Question

Toppr Admin · Accepted Answer

Work done- W-MB-1-x2212-cos-x3B8-20-xD7-0-3-1-x2212-cos30-x2218-6-xD7-1-x2212-x221A-32-3-2-x2212-x221A-3-

A magnet of magnetic moment $20 C G S$ units is freely suspended in a uniform magnetic field of intensity $0.3 C G S$ units. The moment of work done in deflecting it by an angle of $30^{\circ}$ in $C G S$ units is
$6$
$3 (2 - \sqrt{3})$
$3 \sqrt{3}$
$3$

Work done, $W = M B (1 - cos θ)$
$= 20 \times 0.3 (1 - cos 30^{\circ})$
$= 6 \times (1 - \frac{\sqrt{3}}{2}) = 3 (2 - \sqrt{3})$ .

A magnet of magnetic moment 20 CGS units is freely suspended in a uniform magnetic field of intensity 0.3 CGS units. The moment of work done in deflecting it by an angle of 30∘ in CGS units is63(2−√3)3 √33

Work done, W=MB(1−cosθ)=20×0.3(1−cos30∘)=6×(1−√32)=3(2−√3).

A magnet of magnetic moment $20 C G S$ units is freely suspended in a uniform magnetic field of intensity $0.3 C G S$ units. The moment of work done in deflecting it by an angle of $30^{\circ}$ in $C G S$ units is
$6$
$3 (2 - \sqrt{3})$
$3 \sqrt{3}$
$3$

Work done, $W = M B (1 - cos θ)$
$= 20 \times 0.3 (1 - cos 30^{\circ})$
$= 6 \times (1 - \frac{\sqrt{3}}{2}) = 3 (2 - \sqrt{3})$ .