A earned Rs- 80- He spent Rs- 13dfrac-3-5- on food- 25dfrac-1-2- on shopping and Rs- 4dfrac-2-5- on groceries- How much did he save-

Question

Toppr Admin · Accepted Answer

A- Total earned - Rs- 80-xA0-xA0- Amount carned -80-x2212-1335-2512-425-xA0-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-80-x2212-685-512-225-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-80-x2212-905-512-80-x2212-180-125510-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-80-x2212-43510-80-x2212-43-5-36-5Rs

A man earned $R s . 80$ . He spent $R s . 13 \frac{3}{5}$ on food, $25 \frac{1}{2}$ on shopping and $R s . 4 \frac{2}{5}$ on groceries. How much did he save.

A] Total earned = Rs. 80

Amount carned $= 80 - (13 \frac{3}{5} + 25 \frac{1}{2} + 4 \frac{2}{5})$

$= 80 - (\frac{68}{5} + \frac{51}{2} + \frac{22}{5})$

$= 80 - (\frac{90}{5} + \frac{51}{2}) = 80 - (\frac{180 + 1255}{10})$

$= 80 - (\frac{435}{10}) = 80 - 43.5 = 36.5 R s$

A man earned Rs.80. He spent Rs.1335 on food, 2512 on shopping and Rs.425 on groceries. How much did he save.

A] Total earned = Rs. 80 Amount carned =80−(1335+2512+425) =80−(685+512+225) =80−(905+512)=80−(180+125510) =80−(43510)=80−43.5=36.5Rs

A man earned $R s . 80$ . He spent $R s . 13 \frac{3}{5}$ on food, $25 \frac{1}{2}$ on shopping and $R s . 4 \frac{2}{5}$ on groceries. How much did he save.

A] Total earned = Rs. 80

Amount carned $= 80 - (13 \frac{3}{5} + 25 \frac{1}{2} + 4 \frac{2}{5})$

$= 80 - (\frac{68}{5} + \frac{51}{2} + \frac{22}{5})$

$= 80 - (\frac{90}{5} + \frac{51}{2}) = 80 - (\frac{180 + 1255}{10})$

$= 80 - (\frac{435}{10}) = 80 - 43.5 = 36.5 R s$