A man has twice the mass of a boy and has half the kinetic energy of the boy. The ratio of the speeds of the man and the boy must be:
2:1
4:1
1:4
1:2
A
1:4
B
2:1
C
4:1
D
1:2
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Solution
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MAN: 2m,k2 where m is the mass and k is the kinetic energy of the boy
k2=12×2mV2man
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