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Question

A man of mass 60 kg, standing on a platform, is executing SHM in a vertical plane. The displacement from mean position is y=0.5sin(2πt). The minimum value of frequency (f) for which the man will feel weightlessness at the highest point is :
  1. g/2π
  2. 2g/2π
  3. g/2π
  4. 3g/2π

A
2g/2π
B
g/2π
C
3g/2π
D
g/2π
Solution
Verified by Toppr

w=2πf
A=0.5
a=w2A
For weightlessness we have a=g
Thus
g=w2A
w2=g0.5=2g
4π2f2=2g
f2=g2π2;f=2g2π

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