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>> $A man of mass 60 kg, standing on a platf$

Question

A man of mass 60 kg, standing on a platform, is executing SHM in a vertical plane. The displacement from mean position is $y = 0.5 s i n (2 π t)$ . The minimum value of frequency ( $f$ ) for which the man will feel weightlessness at the highest point is :

A

$g / 2 π$

B

$2 g / 2 π$

C

$g / 2 π$

D

$3 g / 2 π$

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Updated on : 2022-09-05

Solution

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Correct option is B)

$w = 2 π f$
$A = 0.5$
$a = - w^{2} A$
For weightlessness we have $a = g$
Thus
$g = - w^{2} A$
$w^{2} = \frac{g}{0 . 5} = 2 g$
$4 π^{2} f^{2} = 2 g$
$f^{2} = \frac{g}{2 π ^{2}}; f = \frac{2 g}{2 π}$

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