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# A man of mass 60 kg, standing on a platform, is executing SHM in a vertical plane. The displacement from mean position is y=0.5sin(2πt). The minimum value of frequency (f) for which the man will feel weightlessness at the highest point is :√g/2π√2g/2π√g/2π√3g/2π

A
2g/2π
B
g/2π
C
3g/2π
D
g/2π
Solution
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#### w=2πfA=0.5a=−w2AFor weightlessness we have a=gThusg=−w2Aw2=g0.5=2g4π2f2=2gf2=g2π2;f=√2g2π

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