Question

A man of mass is on the floor of a lift. Match the following.
List I List II
a) Lift is moving up with acceleration ae) Apparent weight is greater than true weight
b) Lift is moving down with acceleration a f) Apparent weight is zero
c) Lift is moving with uniformly velocityg) Apparent weight is equal to true weight
d) Lift is freely fallingh) Apparent weight is less than true weight

A

a-e, b-h, c-f, d-g

B

a-h, b-e, c-g, d-f

C

a-e, b-h, c-g, d-f

D

a-e, b-f, c-g, d-h

Medium

Solution

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Correct option is C)

When lift accelerates up, pseudo force acts downwards, hence it increases apparent weight. [a-e]
When lift accelerates down, pseudo force acts upwards,  hence it decreases apparent weight [b-h]
When lift moves with uniform velocity there is no pseudo force, hence there is no change in weight. [c-g]
When lift falls freely, it accelerates with g downwards, causing an upwards pseudo force in the frame of the lift equal to mg. Hence total force is 0. So weight is 0. [d-f]

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