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Question

A man raises a box of mass 50 kg to a height of 2 m in 2 minutes, while another man raises the same box to the same height in 5 minutes. What is the ratio of work done by them ?
  1. 2:1
  2. 1:2
  3. 1:1
  4. 4:1

A
2:1
B
1:2
C
1:1
D
4:1
Solution
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Work=Fscosθ
where, F is the force applied, s is the displacement, and θ is the angle between the force applied and displacement

Hence, work done is independent of time taken.

In the given cases, θ=0 as the force applied are in the same direction. Also, F=mg
So W=Fs=mgs

In both the cases, mass and displacement are the same.
W=50×10×2=1000J

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