A sells a car to his friend 10- loss- If the friend sells it Rs-54000 and gains 20- then the original C-P of the car was - -Rs- 45000Rs- 37500RS- 50000Rs- 60000

Question

Toppr Admin · Accepted Answer

Let original C-P was x-Then S-P for man-xA0- x-x2212-10x100-90x100-S-P for friend -90x100-0-2-xD7-90x100-108x100 which is given as 54000- i-e x-54000-xD7-100108-50000-xA0-hence C is right option-

A man sells a car to his friend at $10$ % loss. If the friend sells it for Rs. $54000$ and gains $20$ % then the original $C . P$ of the car was ______ .
Rs. $45000$
Rs. $37500$
RS. $50000$
Rs. $60000$

Let original $C . P$ was $x$ .
Then $S . P$ for man $x - \frac{10 x}{100} = \frac{90 x}{100}$ .

S.P for friend $= \frac{90 x}{100} + 0.2 \times \frac{90 x}{100} = \frac{108 x}{100}$ which is given as $54000$ , i.e $x = \frac{54000 \times 100}{108} = 50000$ ,
hence $C$ is right option.

A man sells a car to his friend at 10% loss. If the friend sells it for Rs.54000 and gains 20% then the original C.P of the car was ______ .Rs. 45000Rs. 37500RS. 50000Rs. 60000

Let original C.P was x.Then S.P for man x−10x100=90x100.S.P for friend =90x100+0.2×90x100=108x100 which is given as 54000, i.e x=54000×100108=50000, hence C is right option.

A man sells a car to his friend at $10$ % loss. If the friend sells it for Rs. $54000$ and gains $20$ % then the original $C . P$ of the car was ______ .
Rs. $45000$
Rs. $37500$
RS. $50000$
Rs. $60000$

Let original $C . P$ was $x$ .
Then $S . P$ for man $x - \frac{10 x}{100} = \frac{90 x}{100}$ .

S.P for friend $= \frac{90 x}{100} + 0.2 \times \frac{90 x}{100} = \frac{108 x}{100}$ which is given as $54000$ , i.e $x = \frac{54000 \times 100}{108} = 50000$ ,
hence $C$ is right option.