Selling price rate of pipes =12 Rs. eachLet cost price of a pipe on which he gain 20% be X Rs
and another pipe on which he lost 20% be Y Rs.
Solving for pipe on which man gains 20%
We know that, Selling price=Cost price+profit
⇒12=X+20% of X
⇒12=X+0.2X
⇒12=1.2X
⇒X=121.2
∴X=10 Rs
Now, Solving for pipe on which man loses 20%
We know that, Selling price=Cost price−loss
⇒12=Y−20% of Y
⇒12=Y−0.2Y
⇒12=0.8Y
⇒Y=120.8
∴Y=15 Rs
Now, Total Cost price=X+Y=10+15=25 Rs
and Total Selling price=2×12=24 Rs
Since Selling price<CostPrice
So, in whole transaction, there is a Loss of 25−24=1 Rs