A man starts repaying a loan as first instalment of Rs. 100. If he increases the instalment by Rs. 5 every month, what amount he will pay in the 30th instalment.
A.P. with the first term = 100 and common difference = 5.
30th=a+(n−1)d
⟹100+(30−1)5
⟹100+29×5
|implies100+145
⟹245