Question

A man with normal near point (25 cm) reads a book with small print using a magnifying glass: a thin convex lens of focal length 5 cm.

(a) What is the closest and the farthest distance at which he should keep the lens from the page so that he can read the book when viewing through the magnifying glass?(b) What is the maximum and the minimum angular magnification (magnifying power) possible using the above simple microscope?

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Updated on : 2022-09-05

Solution

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$f=25cm$

least distance of distance vision, $d=25cm$

closed object distance is $u$.

Image distance $v=−d=−25cm$.

$v1 −u1 =f1 ⇒u=−4.167≈−4.2$

Hence closest distance to resd book is 4.2 cm

Hence closest distance to resd book is 4.2 cm

for the farthest distance, $v=∞$

$v1 −u_{1}1 =f1 ⇒u_{1}=−5$

Hence the farthest distance at which person can read the book is $5cm$.

(b)

maximum angular magnification,

$α=d/∣u∣=25/∣−4.167∣=6$

minimum angular magnification,

$α=d/∣u_{1}∣=25/∣5∣=5$

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