A mass is suspended from a spring having spring constant ' $K$ ' is displaced vertically and released, it oscillates with period ' $T$ '. The weight of the mass suspended is ( $g =$ gravitational acceleration)
$\frac{K T g}{4 π^{2}}$
$\frac{K T^{2} g}{4 π^{2}}$
$\frac{K T g}{2 π^{2}}$
$\frac{K T^{2} g}{2 π^{2}}$

Question

A mass is suspended from a spring having spring constant ' $K$ ' is displaced vertically and released, it oscillates with period ' $T$ '. The weight of the mass suspended is ( $g =$ gravitational acceleration)
$\frac{K T g}{4 π^{2}}$
$\frac{K T^{2} g}{4 π^{2}}$
$\frac{K T g}{2 π^{2}}$
$\frac{K T^{2} g}{2 π^{2}}$

Toppr Admin · Accepted Answer

The correct option is B KT2g4-x3C0-2Time period of the suspended mass executing SHM -xA0-T-2-x3C0-x221A-MKSquaring both sides- we get the value of mass suspended-Mass M-T2K4-x3C0-2Thus weight of mass suspended W-Mg-x27F9- W-KT24-x3C0-2g

A mass is suspended from a spring having spring constant 'K' is displaced vertically and released, it oscillates with period 'T'. The weight of the mass suspended is (g= gravitational acceleration)KTg4π2KT2g4π2KTg2π2KT2g2π2

The correct option is B KT2g4π2Time period of the suspended mass executing SHM T=2π√MKSquaring both sides, we get the value of mass suspended.Mass M=T2K4π2Thus weight of mass suspended W=Mg⟹ W=KT24π2g