A mass m is suspended from a spring of force constant k. The angular frequency of oscillation of the spring will be
km
√mk
mk
√km
A
km
B
mk
C
√mk
D
√km
Open in App
Solution
Verified by Toppr
Referring Formula 1, we get ω=√km . Hence, option D is correct.
Was this answer helpful?
1
Similar Questions
Q1
A mass m is suspended from a spring of force constant k. The angular frequency of oscillation of the spring will be
View Solution
Q2
A weightless spring which has a force constant ′k′ oscillates with frequency ′n′ when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from it. The frequency of oscillation will now become-
View Solution
Q3
A mass m is suspended from a spring of spring constant K and just touches another identical spring fixed to the floor as shown in the figure. The time period of small oscillations is
View Solution
Q4
A weightless spring which has a force constant k oscillates with frequency f when a mass m is suspended from it. The spring is cut into two halves and a mass 2m is suspended from one of the halves. The frequency of oscillation will now be
View Solution
Q5
Given M is the mass suspended from a spring of force constant k. The dimensional formula for [M/k]1/2 is same as that for: