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Question

A metal plate is introduces between the plates of a charged parallel plate capacitor. What is its effect on the capacitance of the capacitor

Solution
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By introducing the metal plate between the plates of charged capacitor, the capacitance of capacitor increases
Reason: It is thickness of metal plate, then
$$ C= \dfrac{\varepsilon oA}{d-t(1-\dfrac{1}{k})} $$
For metal plate K= $$\infty $$, $$ C=\dfrac{\varepsilon oA}{(d-t)} $$

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