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Question

A metal plate of thickness half the separation between the capacitor plates of capacitance C is inserted. The new capacitance is:


  1. C
  2. C2
  3. zero
  4. 2C

A
C
B
C2
C
zero
D
2C
Solution
Verified by Toppr

Initial capacitance =ε0Ad
Now after metal plate is inserted it behaves as two capacitor plates in series with capacitance ε0A(da)
We know when capacitance are in series
1Ceff=1C1+1C2
1Ceff=d4ε0A+d4ε0A
Ceff=2ε0Ad.
Now Ceff=2C
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